0=0.01x^2+4x-6000

Solution for 0=0.01x^2+4x-6000 equation:

0=0.01x^2+4x-6000

We move all terms to the left:

0-(0.01x^2+4x-6000)=0

We add all the numbers together, and all the variables

-(0.01x^2+4x-6000)=0

We get rid of parentheses

-0.01x^2-4x+6000=0

a = -0.01; b = -4; c = +6000;
Δ = b2-4ac
Δ = -42-4·(-0.01)·6000
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*-0.01}=\frac{-12}{-0.02}
=+600
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*-0.01}=\frac{20}{-0.02}
=-1000
$